24. Solution: Pooling Mechanics
Solution
The answer is 2x2x5 . Here's how it's calculated using the formula:
(4 - 2)/2 + 1 = 2
(4 - 2)/2 + 1 = 2
The depth stays the same.
Here's the corresponding code:
input = tf.placeholder(tf.float32, (None, 4, 4, 5))
filter_shape = [1, 2, 2, 1]
strides = [1, 2, 2, 1]
padding = 'VALID'
pool = tf.nn.max_pool(input, filter_shape, strides, padding)
The output shape of
pool
will be [1, 2, 2, 5], even if
padding
is changed to
'SAME'
.